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Join date: May 14, 2022

IB Question Bank Physics V2 (2022) 1. The following problems are equivalent to finding the Lorentz factor . (1 marks) Questions; Test yourself (click on your answer); Mind flash (by Chris Hamper); Slides; IB Physics notes 2; 2.1 Worked examples . Question. The surface of an object moves with constant velocity, V, perpendicular to a light wave directed towards it. The surface is at a distance, R, from the object. The ray path is labelled ‘E’ and the angle between the ray and the velocity vector of the surface is labelled ‘θ’. The three questions below are about the light-speed paradox. (1 marks) The equivalence principle — in this case, how does matter move at speeds greater than c? Shows 0 related questions. 2. Calculate the momentum of the photon being emitted from a moving electron by assuming it is a non-relativistic particle in vacuum (a photon in vacuum) as follows (1 marks) Poynting flux gives P-Q (Q is a function of the momentum) Here the integral is divided into two parts, so the question is whether the two parts add up to P. 1. Use the equation for momentum in terms of energy, energy in terms of wave-length, and the equation for energy in terms of momentum, to show that P=P2+P1. The momentum P and energy E are given as follows: Energy (in joules) is equal to the product of the wave-length of the light (in metres), and energy per metre per second (in joules per metre per second). Momentum (in joules per metre per second) is equal to the product of the frequency (in metres per second) and the wave-length of the light (in metres). The answer is in the second column. Note that this is a trivial example of vector algebra. One way to do it is to use the equation for change of momentum due to an acceleration given above and simplify using the equation for kinetic energy, giving a formula for kinetic energy in terms of momentum. 1. A disc in circular motion at speed v is emitting light with a wave-length of . What is the speed of the emitted light? (1 marks) The wave-length is proportional to the product of the momentum and the speed of the emitting source. Momentum is proportional to the kinetic energy of the

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